분류 전체보기(36)
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#18 (C) bit_operator.c
#include int main(void) { int op = 24 & 18; int op2 = 24 || 18; int op3 = 24 ^ 18; int op4 = ~24; printf("& op: %d\n", op); printf("|| op: %d\n", op2); printf("^ op: %d\n", op3); printf("NOT op: %d\n", op4); return 0; /* Operator AND [&] - return 1 when both of bits are 1 0 & 0 -> return 0 0 & 1 -> return 0 1 & 0 -> return 0 1 & 1 -> return 1 Operator OR [||] - return 1 when one of bits is 1 0 |..
2022.09.17 -
#17 (C) data_expression.c
#include int main(void) { int num1 = 0xC7, num2 = 0xD3; //Hexadecimal int num3 = 043, num4 = 054; //Octal printf("Decimal of num1: %d\n", num1); printf("Decimal of num2: %d\n", num2); printf("Decimal of num3: %d\n", num3); printf("Decimal of num4: %d\n", num4); return 0; /* float num = 0; int i; for (i=0; i
2022.09.17 -
#16 (C) scanf_questions.c
#include int main(void) { /* Question 1 int num1, num2; int sub, mult; printf("Enter the two integers: "); scanf("%d %d", &num1, &num2); sub = num1 - num2; mult = num1*num2; printf("sub: %d\n", sub), printf("mult: %d\n", mult); ------------------------------------------------------------- Question 2 int num1, num2, num3, result; printf("Enter the three integers: "); scanf("%d %d %d", &num1, &num..
2022.09.16 -
#15 (C) scanf_basic.c
#include int main(void) { int num1, num2, num3; printf("Enter three numbers: "); scanf("%d %d %d", &num1, &num2, &num3); printf("num1: %d\n", num1); printf("num2: %d\n", num2); printf("num3: %d\n", num3); return 0; } Output: Enter three numbers: 1 2 3 num1: 1 num2: 2 num3: 3
2022.09.16 -
#14 (C) Comma Operator
#include int main(void) { int num1 =1, num2 =3; ++num1, num2++; printf("Comma "), printf("Operator\n"); printf("num1: %d\n", num1), printf("num2: %d\n", num2); return 0; } Output: Comma Operator num1: 2 num2: 4
2022.09.16 -
#13 (C) operators6.c
#include int main(void) { int num1 = 4; int num2 = 5; int result1, result2, result3; result1 = (num1 == 4 && num2 == 5); result2 = (num16); result3 = (!num1); printf("result1: %d\n", result1); printf("result1: %d\n", result1); printf("result3: %d\n", result3); } Output: result1: 1 result1: 1 result3: 0
2022.09.16